Move Merklist summary to second cell; move drafts to other branch

This commit is contained in:
infogulch 2021-07-07 20:17:54 +00:00
parent ba78bd0834
commit 7b02cb1546
3 changed files with 9 additions and 153 deletions

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"id": "83dd7287-bca5-49f9-b927-31bbc519d5b9",
"metadata": {},
"source": [
"# Merklist"
]
},
{
"cell_type": "markdown",
"id": "bf97974c-5582-4bf5-8ed8-6c43daf5036c",
"metadata": {},
"source": [
"# Merklist\n",
"Using matrix multiplication's associativity and non-commutativity properties provides a natural definition of a cryptographic hash / digest / summary of an ordered list of elements. Due to the non-commutativity property, lists that only differ in element order result in a different summary. Due to the associativity property, arbitrarily divided adjacent sub-lists can be summarized independently and combined to quickly find the summary of their concatenation. This definition provides exactly the properties needed to define a list, and does not impose any unnecessary structure that could cause two equivalent lists to produce different summaries. The name *Merklist* is intended to be reminicent of other hash-based data structures like [Merkle Tree](https://en.wikipedia.org/wiki/Merkle_tree) and [Merklix Tree](https://www.deadalnix.me/2016/09/24/introducing-merklix-tree-as-an-unordered-merkle-tree-on-steroid/)."
]
},

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{
"cells": [
{
"cell_type": "code",
"execution_count": null,
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"cell_type": "markdown",
"id": "203b80b6-7559-4861-ab9c-538885b8d223",
"metadata": {
"tags": []
},
"source": [
"## Inverse?"
]
},
{
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"source": [
"# Q: If you compute the inverse of one of these matrixes and multiply it to the right of the position\n",
"# where it was originally multiplied it should \"delete\" that element as if the element was never added.\n",
"# I'm uncertain of the possibility and frequency of such inverse matrices over finite fields.\n",
"# If this scenario is possible to construct, I think we should \"define\" this operation as deletion.\n",
"\n",
"# See: https://en.wikipedia.org/wiki/Determinant#Properties_of_the_determinant\n",
"\n",
"def det2(mat, m=256):\n",
" ((a, b),\n",
" (c, c)) = mat\n",
" return (a*c - b*c) % m\n",
"\n",
"def det3(mat, m=256):\n",
" ((a, b, c),\n",
" (d, e, f),\n",
" (g, h, i)) = mat\n",
" return (a*e*i + b*f*g + c*d*h - c*e*g - b*d*i - a*f*h) % m\n",
"\n",
"def det(mat, m=256):\n",
" # I dislike having to round here, but it returns a float\n",
" # I wish it returned a native \"B\" type\n",
" return int(round(np.linalg.det(mat),0)) % m\n",
"\n",
"a = ((-2,2,-3),(-1,1,3),(2,0,-1))\n",
"assert_equal(det(a), 18)\n",
"assert_equal(det(a), det3(a))\n",
"\n",
"# ?\n",
"# assert that they didn't change since the last time I ran it\n",
"assert_equal(det(f1), 128)\n",
"assert_equal(det(f2), 160)\n",
"assert_equal(det(f3), 128)"
]
},
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"cell_type": "markdown",
"id": "568ad4ed-7894-465b-9bf3-f19f2269c0f3",
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"source": [
"[This](https://math.stackexchange.com/questions/273054/how-to-find-matrix-inverse-over-finite-field) suggests to find the inverse matrix by first finding the adjugate then applying\n",
"\n",
"> (1/det(A))adj(A)=inv(A)\n",
"\n",
"Under mod p\n",
"\n",
"---\n",
"\n",
"The [adjugate](https://en.wikipedia.org/wiki/Adjugate_matrix) is the inverse of the cofactor matrix.\n",
"\n",
"---\n",
"\n",
"The cofactor matrix is made by multiplying the matrix minor of each (i,j) of the original matrix times a sign factor.\n",
"\n",
"---\n",
"\n",
"The (i,j)-minor of matrix A is the determinant of the matrix A with row i & column j removed."
]
}
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{
"cells": [
{
"cell_type": "markdown",
"id": "d6b5f16e-76a4-473f-a8cd-efd532f8673f",
"metadata": {},
"source": [
"# Merklist Tree\n",
"\n",
"Part 2 of the Merklist idea. Constructing a tree structure of summarized sublists, so that mutations to the list can be computed, verified, and stored using $O(log(N))$ time and space.\n",
"\n"
]
}
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